Let lambda1lambda1, lambda2lambda2, and aa be three fixed complex algebraic
numbers.
For a given integer nn, write
Theta(n)=arg(alambdan1+lambdan2)Theta(n)=arg(alambdan1+lambdan2).
Assuming Theta(n)Theta(n) is not zero, I am looking for 'good' lower bounds on
|Theta(n)||Theta(n)|. By 'good' I mean that if |Theta(n)|>B(n)|Theta(n)|>B(n),
then 1/B(n)1/B(n) should asymptotically grow slower that any exponential in nn.
Is there a way to use one of Baker's theorems (which provide effective
lower bounds on linear combinations of logs of algebraic numbers) to achieve
this?
For example, writing instead Gamma(n)=arg(alambdan1lambdan2)Gamma(n)=arg(alambdan1lambdan2)
(say), one can get polynomial bounds on |Gamma(n)||Gamma(n)|: noting that
displaystyleGamma(n)=logleft(fracalambdan1lambdan2|alambdan1lambdan2|right)=loga+nloglambda1+nloglambda2−log|a|−nlog|lambda1|−nlog|lambda2|displaystyleGamma(n)=logleft(fracalambdan1lambdan2|alambdan1lambdan2|right)=loga+nloglambda1+nloglambda2−log|a|−nlog|lambda1|−nlog|lambda2|
we can apply e.g. Baker-Wustholz (1993) to the above linear form
and get a lower bound |Gamma(n)|>C(n) (assuming that |Gamma(n)| is non-zero)
such that 1/C(n) is in fact bounded by a fixed polynomial in n.
The problem in getting a similar lower bound for |Theta(n)| is that, even though
Theta(n) can be written as a linear combination of logs of algebraic
numbers of constant degree, as for Gamma(n), the height of the
algebraic number alambdan1+lambdan2 is potentially exponential in
n, and it does not seem that taking logs will help here.
The critical case is of course when lambda1 and lambda2 have the
same magnitude. In fact, I would be happy for an approach with even very
simple values of a, such as a=2.
No comments:
Post a Comment