Tuesday, 8 May 2007

nt.number theory - Can the failure of the multiplicativity of Euler factors at bad primes be corrected?

Warning: This one of those does-anyone-know-how-to-fix-this-vague-problem questions, and not an actual mathematics question at all.



If X is a scheme of finite type over a finite field, then the zeta function Z(X,t) lies in 1+tmathbfZ[[t]]. We can calculate the zeta function of a disjoint union by the formula Z(XamalgY,t)=Z(X,t)Z(Y,t). There is also a formula for Z(XtimesY,t) in terms of Z(X,t) and Z(Y,t), but this is slightly more complicated. In fact, these two formulas are precisely the standard big Witt vector addition and multiplication law on the set 1+tmathbfZ[[t]]. (Actually, there's more than one standard normalization, so you have to get the right one. I believe this ring structure was first written down by Grothendieck in his appendix to Borel-Serre, but I don't know who first made the connection with the ring of Witt vectors as defined earlier by Witt.) If we let K0 be the Grothendieck group on the isomorphism classes of such schemes, where addition is disjoint union and multiplication is cartesian product, then we get a ring map K0to1+tmathbfZ[[t]]. We could also do all this with the L-factor L(X,s)=Z(X,qs) (where q is the cardinality of the finite field) instead of the zeta function. This is because they determine each other.



This is all good. The problem I have is when there is bad reduction. So now let X be a scheme of finite type over mathbfQ (say). Then the L-factor Lp(X,s) is defined by
Lp(X,s)=mathrmdet(1Fpps|H(X,mathbfQell)Ip),
where Ip is the inertia group at p. (Sorry, I'm not going to explain the rest of the notation.) If I acts trivially (in which case one might say X has good reduction), then taking invariants under I does nothing, and so as above, the L-factor of a product and sum of varieties is determined by the individual L-factors. If I does not act trivially, then the L-factor of a sum is again the product of the individual L-factors, but for products there is no such formula! (The following should be an example showing this. Take X=mathrmSpecmathbfQ(i), Y=mathrmSpecmathbfQ(sqrt2). The we have the following Euler factors at 2: L2(X,s)=L2(Y,s)=L2(XtimesY,s)=12s and L2(XtimesX,s)=(12s)2. So the L-factors of two schemes do not determine that of the product.) Therefore the usual Euler factor cannot possibly give a ring map defined on the Grothendieck ring of varieties over mathbfQ.



So, is there a way of fixing this problem? I would guess the answer is No, because while some people might allow you to scale Euler factors by numbers, I don't think anyone will let you change them by anything else. But maybe there is some "refined L-factor" that determines the usual one (and maybe incorporates the higher cohomology of the inertia group?) Assuming there is no known way of repairing things, I have a follow-up question: Is there some general formalism that handles this failure? And if so, how does that work?

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