Let me conisder the case when the distribution of planes is of codimension 1 and explain why in this case it is enough to have C1C1 smoothness in order to ensure the existence of the folitation.
In the case when the distribution is of codimension 1, you can formulate Frobenius Theorem in terms of 1-forms. Namely you can define a non-zero 1-form AA, whose kernel is the distribution. The smoothness of this 1-form will be the same as the smoothness of the distribution. Now, you can say that the distribution is integrable if AwedgedA=0AwedgedA=0. This quantity is well defined is A is C1C1. Let me give a sketch of the proof that AwedgedA=0AwedgedA=0 garanties existence of the foliation is A is C1C1.
The proof is by induction
1) Consider the case n=2n=2. In this case it is a standard fact of ODE, that for a C1C1 smooth distribution of directions on the plane the integral lines are uniquelly defined.
2) Conisder the case n=3n=3. We will show that the foliation exists locally near any point, say the origin OO of R3R3. The 1-form A, that defines the distribution is non vanishing on one of the coordinate planes, say (x,y)(x,y) plane in the neighborhood of OO. Take a C1C1
smooth vector field in the neigborhood of OO that is transversal to planes z=constz=const
and satisfies A(v)=0A(v)=0. Take the flow correponding to this vector field. The flow is C1C1 smooth and moreover it preserves the distribution of planes A=0A=0. Indeed, dA vanishes on the planes A=0 (by the condition of integrability), and we can apply the formula for Lie derivative Lv(A)=d(iv(A))+iv(dA)=iv(dA)Lv(A)=d(iv(A))+iv(dA)=iv(dA). Finally, we take the integral curve of the restriction of A=0A=0 to the plane (x,y)(x,y) and for evey curve conisder the surface it covers unders the flow of vv. This gives the foliation.
This reasoning can be repeated by induction.
A good refference is Arnold, Geometric methods of ordinary differential equations. I don't know if this book was transalted to English
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