It is a well known result (sometimes called the Weyl lemma) that the laplacian in is hypoelliptic, i.e. if is a distribution s.t. is smooth in an open set, than itself is smooth in the same open set. To establish the result one observes that:
1) and than ( are ordinary Sobolev spaces)
2) the same results holds if is replaced by an arbitrary bounded open set . Here one can define {}
3) every distribution lies in some , for some
Then a kind of bootstraping argument and Sobolev embedding gives the result.
1) is very easy to establish (just look at the Fourier transform side), while the local version 2) is harder and requires the "local nature" of the laplacian (in fact of partial differentiation operators), as is encoded for example by the Leibniz rule (Reed and Simon has a complete proof).
Since on the Fourier trasform side one can naturally define a square root of as .
Here comes my question: Is hypoelliptic?
The equivalent of 1) for is trivially true, but 2) seems much harder because appears to be "non local" (the values of on an open set seem to depend on the values of everywhere).
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