- Let mathcalDmathcalD be the nnth Weyl algebra mathcalD:=k[x1,...,xn,partial1,...,partialn]mathcalD:=k[x1,...,xn,partial1,...,partialn], where partialixi−xipartiali=1partialixi−xipartiali=1.
- Let widetildemathcalDwidetildemathcalD be its Rees algebra, which is mathcalD:=k[t,x1,...,xn,partial1,...,partialn]mathcalD:=k[t,x1,...,xn,partial1,...,partialn], where partialixi−xipartiali=tpartialixi−xipartiali=t, and tt is central.
- Let mathcalOXmathcalOX denote the polynomial algebra k[x1,...,xn]k[x1,...,xn], which is a left widetildemathcalDwidetildemathcalD-module, where tt and all the partialipartiali act by zero. NOTE: this is different than the homogenization of the standard mathcalDmathcalD-module structure on mathcalOXmathcalOX.
The question I am interested in is, how many generators does a left ideal MM in widetildemathcalDwidetildemathcalD need before HomwidetildemathcalD(mathcalOX,widetildemathcalD/M)HomwidetildemathcalD(mathcalOX,widetildemathcalD/M) can be non-zero? My conjecture is that MM needs at least n+1n+1 generators. NOTE: Savvy Weyl algebra veterans will know every left ideal in mathcalDmathcalD can be generated by two elements; however, this is not true in widetildemathcalDwidetildemathcalD. There can be ideals generated by n+1n+1 elements and no fewer.
The functor HomwidetildemathcalD(mathcalOX,−)HomwidetildemathcalD(mathcalOX,−) acts as a relative analog of the more familiar functor HomR(k,−)HomR(k,−) (where R=k[t,y1,...yn]R=k[t,y1,...yn]). Therefore, the above question is analogous to asking "how many generators must an ideal IsubseteqRIsubseteqR have before R/IR/I can have depth zero?" The answer here is n+1n+1, which follows from Thm 13.4, pg 98 of Matsumura (essentially a souped up version of the Hauptidealsatz).
In the noncommutative case, if you try to make this work with the widetildemathcalDwidetildemathcalD-module kk (where tt, xixi and partialipartiali all act by zero), it doesn't work. The natural conjecture would be that HomwidetildeD(k,widetildemathcalD/M)neq0HomwidetildeD(k,widetildemathcalD/M)neq0 implies MM had at least 2n+12n+1 generators, except this fails even for the first Weyl algebra and M=widetildemathcalDx1+widetildemathcalDpartial1 (since widetildemathcalD/M=k).
However, it seems that things might work right for the relative module OX, based on a fair amount of experimentation. It is easily true in the first Weyl algebra. Oh, and equivalent condition is to ask when HomoverlinemathcalD(mathcalOX,overlineM)neq0, where overlinemathcalD=widetildemathcalD/t, and overlineM is M/Mt.
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