Sunday, 22 April 2007

dg.differential geometry - Lipschitz equivalence of Riemannian metrics

As Dmitri says any two Riemannian metrics on a compact manifold are Lipschitz equivalent. The proof is quite simple.



Consider gg and hh two metrics on MM, Let UMUM be the unit tangent bundle, since MM is compact, UMUM is compact. Then you see that f:UMtomathbbRf:UMtomathbbR defined by f(x)=fracg(x,x)h(x,x)f(x)=fracg(x,x)h(x,x) is continuous and strictly positive. By compactness, it is bounded above and below by positive constants.

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