There is the following adjointness (a form of Frobenius reciprocity):
HomG(rho,FX)=HomH(rho,trivial).
Thus rho embeds in FX if and only if rho admits a non-trivial H-fixed quotient.
(If H is finite and F has characteristic zero, or at least prime to the order
of H, so that rho is semi-simple
as an H-representation, then this is equivalent to requiring that rho have a
non-trivial H-fixed subrepresentation.)
(Note also that a non-zero G-equivariant map out of rho is automatically injective,
because rho is irreducible.)
No comments:
Post a Comment