Assuming has the structure for defining convolutions I don't think it is ever an algebra homomorphism. Take to be supported on , i.e. take some set of non-zero measure in and let be a function whose support lies in that set, then but so .
Edit: Scratch what I said. I was confusing sub--algebra with sub-algebra of random variables and even in the finite case my statement is completely incorrect. In almost every instance will not be zero as Jonas points out in the comments.
No comments:
Post a Comment